4p+25=-p^2+30p

Solution for 4p+25=-p^2+30p equation:

4p+25=-p^2+30p

We move all terms to the left:

4p+25-(-p^2+30p)=0

We get rid of parentheses

p^2-30p+4p+25=0

We add all the numbers together, and all the variables

p^2-26p+25=0

a = 1; b = -26; c = +25;
Δ = b2-4ac
Δ = -262-4·1·25
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-24}{2*1}=\frac{2}{2}
=1
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+24}{2*1}=\frac{50}{2}
=25
$